Tuesday, May 24, 2016

HOW MANY ATOMS IS 1 (one/uno) GRAMS OF GOLD (Au)? THIS WHERE THE EVOLUTIONISTS AND SUPERSTITIOUS ALCHEMISTS FAIL TO SEE THE VAST COMPLEXITY BEYOND THEIR SMALL MINDS...!




GOLD 1$ Coin - In which God does USA trust? Because the BIBLE God is "crazy"...!!!






HOW MANY ATOMS IS 1 (one/uno) GRAMS OF GOLD (Au)?

THIS WHERE THE EVOLUTIONISTS AND SUPERSTITIOUS ALCHEMISTS FAIL TO SEE THE VAST COMPLEXITY BEYOND THEIR SMALL MINDS:


AMAZING but easy as to the accepted and highly true PERIODIC TABLE of ELEMENTS and calculation of ATOMS and COMPONENTS and CHARACTERISTICS DATA...!

http://www.chemteam.info/Mole/Avogadro-Number-CalcsII.html
http://www.sciencegeek.net/tables/tables.shtml
https://en.wikipedia.org/wiki/Periodic_table
https://en.wikipedia.org/wiki/Gold



Problem #8: How much does 100 million atoms of gold weigh?

Solution:

1) Determine moles of gold in 1.000 x 108 (we'll assume four sig figs):

    1.000 x 108 atoms divided by 6.022 x 1023 atoms/mol = 1.660577881 x 10¯16 mol

2) Determine grams in 1.66 x 10¯16 mol of gold:

    1.660577881 x 10¯16 mol times 196.97 g/mol = 3.271 x 10¯14 g (to four sig fig)


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https://answers.yahoo.com/question/index?qid=20101008093618AAi83eQ

How many atoms of gold(proton number 79) are there in a pure gold ring with a mass of 3.94g?


Best Answer:  atomic weight of Au (gold)=196.97
Avogadro's number=6.022X10^23

(3.94 g)/(196.97 g/mol)=.02 mol
.020 mol X 6.022X10^23=1.20X10^23 atoms

the atomic weight of an atom, or molecule, tells you the number of grams per mole. therefore you must divide the mass

of your object, the ring, by the atomic weight to find out the number of moles contained within the object. You then

multiply the number of moles by Avogadro's number, which is the number of atoms or molecules per mole, to find out how

many atoms or molecules, atoms in this case, contained in your object.

Hope that all made sense :).




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THIS WHERE THE EVOLUTIONISTS AND SUPERSTITIOUS ALCHEMISTS FAIL TO SEE THE VAST COMPLEXITY BEYOND THEIR SMALL MINDS:

SO 1.0g of gold must be around:

atomic weight of Au (gold)=196.97
Avogadro's number=6.022X10^23


(1.0 g)/(196.97 g/mol) = 0.005076915 mol
0.005076915 mol x 6.022X10^23 = 3.057318373 x 10^21 ATOMS of Gold (Au) that have


30,573,183,730,000,000,000 = 30.573 Billion-Billion Atoms of Gold in 1 gram.


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...this amount of atoms creates a nearly impossible if not impossible, abyss and barrier to the human making of GOLD(Au) from LEAD(Pb) or other ELEMENT, by the mere elimination of a few electrons...!


...SO FOLKS if EVOLUTION wants to make the first LIFE FORM of a UNICELLULAR CELL in a LABORATORY, it could be more complex, than TRYING TO MAKE GOLD(Au)...!



...BUT when we are in the face of UNSUSPECTING and NAIVE if not INCAPABLE OR INCOMPETENT PhD SCIENCE Evolutionists, IT IS BECAUSE THEY LACK a real understanding of the COMPLEXITY of the PROBLEMS in QUESTION...! And of what it really takes to MAKE HAPPEN Life and ELEMENTS...!!!

BUT REST ASSURED that NOR Jesus nor God, has anything to do with it, as they are a mere myth story as such...!


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